CONCACAF Championship | |
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![]() 1991 CONCACAF Gold Cup official programme | |
Tournament details | |
Host country | United States |
Dates | June 28 – July 7 |
Teams | 8 (from 1 confederation) |
Venue(s) | 2 (in 2 host cities) |
Final positions | |
Champions | ![]() |
Runners-up | ![]() |
Third place | ![]() |
Fourth place | ![]() |
Tournament statistics | |
Matches played | 16 |
Goals scored | 50 (3.13 per match) |
Attendance | 397,124 (24,820 per match) |
Top scorer(s) | ![]() (4 goals) |
Best player(s) | ![]() |
The 1991 CONCACAF Gold Cup was the first edition of the Gold Cup, the soccer championship of North America, Central America and the Caribbean (CONCACAF), and the eleventh overall CONCACAF tournament. The last time the CONCACAF Championship was held was 1971, from that point on the first-place finishers of World Cup qualifying were considered continental champions.[1][2]
The tournament was hosted by the United States and played in the Greater Los Angeles area of California at two venues: the Los Angeles Memorial Coliseum and the Rose Bowl. The eight teams were broken up into two groups of four; the top two teams of each group would advance to the semifinals. The Gold Cup was won by the United States, who eliminated Mexico in the semi-finals match, and went on to beat Honduras on penalties after tying them in the final 0–0.